AMC 8 · 2011 · #9
Easy mode Grade 6Problem
Carmen went on a long bike ride. The graph shows how many miles she had ridden as time passed.
By the end of the ride, the graph shows she rode 35 miles in 7 hours.
What was her average speed in miles per hour?
Pick an answer.
AMC 8 2011 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Try it yourself first — the explanation is most useful after you’ve attempted it.
Toolkit + CCSS Solution
Understand
Restated: Carmen rides her bike on a hilly highway. A graph plots her cumulative distance (in miles) against time (in hours). The graph starts at $(0, 0)$ and ends at $(7, 35)$, with bends at $(1, 5)$, $(2, 15)$, and $(4, 20)$. What is her average speed for the entire ride in miles per hour?
Givens: The graph plots miles (vertical) against hours (horizontal); The ride starts at the origin $(0, 0)$; The final point on the graph is $(7, 35)$ — $7$ hours, $35$ miles; Intermediate bends at $(1, 5)$, $(2, 15)$, $(4, 20)$ show changing pace on hills; Answer choices: (A) $2$, (B) $2.5$, (C) $4$, (D) $4.5$, (E) $5$ (mph)
Unknowns: Carmen's average speed for the entire ride, in miles per hour (mph)
Understand
Restated: Carmen rides her bike on a hilly highway. A graph plots her cumulative distance (in miles) against time (in hours). The graph starts at $(0, 0)$ and ends at $(7, 35)$, with bends at $(1, 5)$, $(2, 15)$, and $(4, 20)$. What is her average speed for the entire ride in miles per hour?
Givens: The graph plots miles (vertical) against hours (horizontal); The ride starts at the origin $(0, 0)$; The final point on the graph is $(7, 35)$ — $7$ hours, $35$ miles; Intermediate bends at $(1, 5)$, $(2, 15)$, $(4, 20)$ show changing pace on hills; Answer choices: (A) $2$, (B) $2.5$, (C) $4$, (D) $4.5$, (E) $5$ (mph)
Plan
Primary tool: #8 Analyze the Units
Secondary: #3 Draw a Picture
The question asks for a rate in miles per hour, which screams Tool #8 (Analyze the Units): $\text{mph} = \dfrac{\text{miles}}{\text{hours}}$, so we just need one number for total miles and one number for total hours. Tool #3 (Draw a Picture) is already done for us — the graph is the picture — but we have to read it correctly: only the final point $(7, 35)$ matters for the average, because everything in between is just "how she got there". The intermediate bends are a distractor that tempts students to average the segment speeds, which is wrong.
Execute — Answer: E
5.G.A.2 Step 1 - Read the total time from the horizontal axis.
- The ride ends at the rightmost point of the graph, which sits at $x = 7$ on the hours axis.
- So the ride lasted $7$ hours.
💡 Reading the $x$-coordinate of a point in the first quadrant to recover "how much time" is a Grade 5 coordinate-plane skill.
5.G.A.2 Step 2 - Read the total distance from the vertical axis.
- The same final point sits at $y = 35$ on the miles axis.
- So Carmen rode a total of $35$ miles.
💡 Reading the $y$-coordinate of the endpoint gives the cumulative distance — the same Grade 5 coordinate-plane idea.
6.RP.A.3 Step 3 Apply the definition of average speed: total distance divided by total time, with units already matched (miles and hours), so the answer comes out directly in mph.
💡 Computing a unit rate (miles per hour) from a total distance and a total time is core Grade 6 rate reasoning.
5.G.A.2 Read the total time from the horizontal axis. The ride ends at the rightmost poi 5.G.A.2 Read the total distance from the vertical axis. The same final point sits at $y 6.RP.A.3 Apply the definition of average speed: total distance divided by total time, wit Review
Reasonableness: A casual bike ride on a hilly highway at about $5$ mph is reasonable — closer to a brisk walk than a sport ride, which fits "hilly" terrain. Checking the segments: $0 \to 5$ mi in $1$ hr ($5$ mph), $5 \to 15$ mi in $1$ hr ($10$ mph downhill), $15 \to 20$ mi in $2$ hr ($2.5$ mph uphill), $20 \to 35$ mi in $3$ hr ($5$ mph). The total $5 + 10 + 5 + 15 = 35$ mi over $1 + 1 + 2 + 3 = 7$ hr confirms $35 / 7 = 5$ mph.
Alternative: Tool #6 (Guess and Check) by ruling out the trap. Students who naively average the segment speeds get $\tfrac{5 + 10 + 2.5 + 5}{4} = 5.625$ mph, which isn't even a choice — a warning that "average speed" is not the same as the average of speeds. Only $\dfrac{\text{total distance}}{\text{total time}}$ matches a listed choice.
CCSS standards used (min grade 6)
5.G.A.2Represent real-world and mathematical problems by graphing points in the first quadrant (Reading the endpoint $(7, 35)$ off the distance-vs-time graph to extract the total time ($7$ hours) and total distance ($35$ miles).)6.RP.A.3Use ratio and rate reasoning to solve real-world and mathematical problems (Computing the average speed as the unit rate $35 \div 7 = 5$ miles per hour.)
⭐ Average speed always means total distance $\div$ total time — not the average of the speeds along the way!
⭐ Average speed always means total distance $\div$ total time — not the average of the speeds along the way!
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